8L=(k)B^2D^3

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Solution for 8L=(k)B^2D^3 equation: 



8=(L)^2^3

We move all terms to the left:

8-((L)^2^3)=0

determiningTheFunctionDomain
-L^2^3+8=0

We move all terms containing L to the left, all other terms to the right

-L^2^3=-8

L=-8/1

L=-8

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